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Draft:1989 SEC women's basketball tournament

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1989 SEC women's basketball tournament
ClassificationDivision I
Teams10
SiteAlbany Civic Center
Albany, Georgia
ChampionsTennessee (4th title)
Winning coachPat Summitt (4th title)
MVPBridgette Gordon (Tennessee)
← 1988
1990 →
1988–89 SEC women's basketball standings
Conf Overall
Team W   L   PCT W   L   PCT
No. 2 Auburn 9 0   1.000 32 2   .941
No. 1 Tennessee 8 1   .889 35 2   .946
No. 10 Georgia 6 3   .667 23 7   .767
Vanderbilt 5 4   .556 21 8   .724
LSU 5 4   .556 19 11   .633
Ole Miss 4 5   .444 23 8   .742
Mississippi State 3 6   .333 12 16   .429
Kentucky 3 6   .333 12 16   .429
Florida 1 8   .111 15 14   .517
Alabama 1 8   .111 14 15   .483
1989 SEC tournament winner
Rankings from AP poll


The 1989 SEC women's basketball tournament took place March 3 to March 6, 1989, at the Albany Civic Center in Albany, Georgia.

Number two seed Tennessee won the tournament by beating No. 1 seed Auburn in the championship game.[1]

Tournament

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First round
Friday, March 3
Second round
Saturday, March 4
Semifinals
Sunday, March 5
Championship game
Monday, March 6
            
8 Kentucky 64
9 Florida 67
1 Auburn 72
9 Florida 61
1 Auburn 75
5 LSU 65
4 Vanderbilt 73
5 LSU 79
1 Auburn 51
2 Tennessee 66
3 Georgia 69
6 Ole Miss 78
6 Ole Miss 60
2 Tennessee 82
2 Tennessee 89
10 Alabama 61
7 Mississippi State 55
10 Alabama 59

Asterisk denotes game ended in overtime.

All-Tournament team

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References

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  1. ^ "SEC Women's Basketball Tournament History" (PDF). a.espncdn.com. Retrieved April 8, 2024.