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1867 Minnesota Attorney General election

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1867 Minnesota Attorney General election

← 1865 5 November 1867 1869 →
 
Nominee Francis R. E. Cornell Andrew G. Chatfield
Party Republican Democratic
Popular vote 34,657 28,918
Percentage 53.84% 44.92%

Attorney General before election

William J. Colvill
National Union

Elected Attorney General

Francis R. E. Cornell
Republican

The 1867 Minnesota Attorney General election was held on 5 November 1867 in order to elect the attorney general of Minnesota. Republican nominee and former member of the Minnesota House of Representatives Francis R. E. Cornell defeated Democratic nominee and former Justice of the Supreme Court of Minnesota Territory Andrew G. Chatfield.[1]

General election

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On election day, 5 November 1867, Republican nominee Francis R. E. Cornell won the election by a margin of 5,739 votes against his opponent Democratic nominee Andrew G. Chatfield, thereby gaining Republican control over the office of attorney general. Cornell was sworn in as the 4th attorney general of Minnesota on 8 January 1868.[2]

Results

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Minnesota Attorney General election, 1867
Party Candidate Votes %
Republican Francis R. E. Cornell 34,657 53.84
Democratic Andrew G. Chatfield 28,918 44.92
Write-in 801 1.24
Total votes 64,376 100.00
Republican gain from National Union

References

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  1. ^ "Attorney General, 1867 Election". electionarchives.lib.umn.edu. Retrieved 5 October 2024.
  2. ^ "MN Attorney General". ourcampaigns.com. 19 March 2024. Retrieved 5 October 2024.